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(X^2)-50X+2.25=0
a = 1; b = -50; c = +2.25;
Δ = b2-4ac
Δ = -502-4·1·2.25
Δ = 2491
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-\sqrt{2491}}{2*1}=\frac{50-\sqrt{2491}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+\sqrt{2491}}{2*1}=\frac{50+\sqrt{2491}}{2} $
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